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15 October, 01:38

What's up solution should be used to rewrite 16 (x^3+1) ^2-22 (x^3+1) - 3=0

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  1. 15 October, 02:07
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    x = cuberoot (-9/8) = - 1.04004 or x = cuberoot (1/2) = 0.7937

    Step-by-step explanation:

    let y = x^3 + 1

    we have:

    16 * (y) ^2 - 22 (y) - 3 = 0

    16 = 2 * 8

    -3 = - 3 * 1

    8*-3 + 2 = - 24 + 2 = - 22

    Factor as (8y + 1) (2y - 3) = 16 (y) ^2 - 22 (y) - 3 = 0

    so (8y + 1) = 0 or 2y - 3 = 0

    y = - 1/8 OR y = 3/2

    with y = x^3 + 1

    solve for x

    -1/8 = x^3 + 1

    x^3 = - 9/8

    x = cuberoot (-9/8)

    about x = - 1.04004

    or 3/2 = x^3 + 1

    1/2 = x^3

    x = cuberoot (1/2) = 0.7937
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