Derivative of sec^2 (x? it equals 2sec^2 (xtan (x but why doesn't the ^2 part disappear? the derivative of sin^2 (x = 2sinxcosx so i thought the ^2 part would disappear in the derivative of sec^2 (x ...

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31 July, 05:41

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Trevor Herring · Answer 1

Y = sec^2 x

use the product rule

dy/dx = sec x * sec x tan x + sec x tan x sec x

= 2 sec^2 tan x

Derivative of sec^2 (x? it equals 2*sec^2 (x*tan (x but why doesn't the ^2 part disappear? the derivative of sin^2 (x = 2sinxcosx so i thought the ^2 part would disappear in the derivative of sec^2 (x ...