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Jaydin Roman
Mathematics
10 February, 12:52
2x-4y=8 3x+8y=-2 solve using elimination
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Rodolfo Conway
10 February, 13:00
0
2 (2x-4y=8) = 4x-8y = 16
3x+8y=-2
4x-8y=16
3x+8y=-2
the 8s cancel out
4x+3x = 14
7x=14
x=2
2 (2) - 4y = 8
4-4y = 8
-4 - 4
-4y=4
y=-1
x=2
y=-1
(2,-1)
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Aryan Jefferson
10 February, 13:08
0
2x+5y=13 multiply both sides by 3
6x + 15y = 39
3x - 4y = 8 multiply both sides by - 2
-6x + 8y = - 16 add the two new equations to each other
(-6x + 8y) + (6x + 15y) = 39 + (-16)
-6x + 6x + 8y + 15y = 39 - 16
0x + 23y = 23
23y = 23
y = 1
2x + 5y = 13 sub in 1 for y
2x + 5 (1) = 13
2x + 5 = 13
2x = 8
x = 4
answer (4,1)
check:
3 (4) - 4 (1) = 8
12 - 4 = 8
8 = 8
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