Sign In
Ask Question
Robert
Mathematics
23 November, 08:43
How to solve for x
12 (x+4) + 3 (-3-2x) = 71
+1
Answers (
2
)
Giles
23 November, 08:59
0
5.333 or 5 1/3
Step-by-step explanation:
12 (x+4) + 3 (-3-2x) = 71
12x+48-9-6x=71
6x+39=71
6x=32
x=5.3333 or 5 1/3
Comment
Complaint
Link
Logan Cervantes
23 November, 09:11
0
Step-by-step explanation:
12 (x+4) + 3 (-3-2x) = 71
12x + 48 - 9 - 6x = 71
12x - 6x = 71 - 48 + 9
6x = 32
x = 32/6
x = 16/3
x = 5 1/3
Comment
Complaint
Link
Know the Answer?
Answer
Not Sure About the Answer?
Find an answer to your question 👍
“How to solve for x 12 (x+4) + 3 (-3-2x) = 71 ...”
in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers
You Might be Interested in
he cost of a 16-ounce soda from a vending machine increases from $2.25 to $2.70. Find the percent increase.
Answers (1)
10x - 9y = - 7 y = 3 need to find x
Answers (2)
Find the slope of the line 2x+5y=-3.
Answers (2)
Parabola Skate Rental rents skate boards for $4.50 per hour with a rental fee of $35. Arc of Hawk Skate Rental rents skate boards for $5.25 per hour with a rental fee of $25
Answers (1)
Value rent-a-car rental a luxury car at a daily rate of $43.09 plus 4 cents per mile. a business person is allotted $100 for car rental each day. how many miles can the business person travel on the $100
Answers (1)
New Questions in Mathematics
If f (x) = 3^x and g (x) = 2x+5, at which value of x is f (x)
Answers (1)
Match each equation with its solution set. Tiles a2 - 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a - 10 = 0 a2 + 5a - 14 = 0 a2 - 5a - 14 = 0 Pairs {-2, 7} {2, - 7} {-2, - 7} {7, 2}
Answers (1)
Eliza is rolling a die and recording whether she gets an even or an odd number. She rolls the die 250 times and records the number that she gets in the table.
Answers (2)
What number is 18% of 250
Answers (2)
0.5 (x+0.1) - 0.1 (x-0.5)
Answers (2)
Home
»
Mathematics
» How to solve for x 12 (x+4) + 3 (-3-2x) = 71
Sign In
Sign Up
Forgot Password?