Find the vertex of the parabola given by y=2x^2-4x-1

Question

Yoselin Lin

Mathematics

23 November, 02:15

Find the vertex of the parabola given by y=2x^2-4x-1

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Parker Mooney · Answer 1

Given the quadratic y = 2x^2-4x-1, I identify A = 2, B = - 4 and C = - 1. The axis of symmety: x = - b/2a - - > 4/2 (2) = 4/4 = 1. Therefore, the x-coordinate of the vertex is 1. To find the y-coordinate, I plug in 1 for x into the quadratic. Hence, y = 2 (1) ^2-4 (1) - 1 - - - > - 3. The coordinates of the vertex are (1,-3).