Two containers designed to hold a water our side-by-side, both in the shape of a cylinder. Container a has A diameter of 6 feet and a height of 15 feet. Container b has a diameter of 8 feet and a height of 10 feet. Container is full of water in the water is pumped into container be until container is empty. After the pumping is complete what is the volume of the empty portion of container b, to the nearest 10th of a cubic foot

Question

Paityn Mckay

Mathematics

10 May, 00:26

Two containers designed to hold a water our side-by-side, both in the shape of a cylinder. Container a has A diameter of 6 feet and a height of 15 feet. Container b has a diameter of 8 feet and a height of 10 feet. Container is full of water in the water is pumped into container be until container is empty. After the pumping is complete what is the volume of the empty portion of container b, to the nearest 10th of a cubic foot

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Raven · Answer 1

78.5 ft3

Step-by-step explanation:

First we need to find the volume of both containers.

The volume of a cylinder is given by the equation:

Volume = pi * diameter^2 * height / 4

If cylinder A has a diameter of 6 feet and height of 15 feet, we have:

Volume_A = pi * 6^2 * 15 / 4 = 424.115 ft3

If cylinder B has a diameter of 8 feet and height of 10 feet, we have:

Volume_A = pi * 8^2 * 10 / 4 = 502.6548 ft3

After pumping the water from A to B, the volume of the empty portion of B will be the difference of their volumes:

Volume_B - Volume_A = 502.6548 - 424.115 = 78.5398 ft3

Rounding to the nearest 10th of a cubic foot, we have a difference of 78.5 ft3