What are the removable discontinuities of the following function?

F (x) = x^2-36 / x^3-36x

A. x=-6, x = 0, and x = 6

B. x=-6 and x = 6

C. x = 0 and x = - 6

D. x = 0 and x = 6

Answer: B

Step-by-step explanation:

f (x) = x^2-36/x^3-36x or

f (x) = (x+6) (x-6) / x (x^2-36) = (x+6) (x-6) / x (x+6) (x-6)

Discontinuities are x=0, x=-6, x=6

f (x) = (x+6) (x-6) / x (x+6) (x-6) = 1/x; x≠0