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22 August, 22:08

What are the removable discontinuities of the following function?

F (x) = x^2-36 / x^3-36x

A. x=-6, x = 0, and x = 6

B. x=-6 and x = 6

C. x = 0 and x = - 6

D. x = 0 and x = 6

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  1. 22 August, 22:36
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    Answer: B

    Step-by-step explanation:

    f (x) = x^2-36/x^3-36x or

    f (x) = (x+6) (x-6) / x (x^2-36) = (x+6) (x-6) / x (x+6) (x-6)

    Discontinuities are x=0, x=-6, x=6

    f (x) = (x+6) (x-6) / x (x+6) (x-6) = 1/x; x≠0
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