6 November, 16:50
What are the solutions of the equation 9x^4 - 2x^2 - 7 = 0? Use u substitution to solve.
6 November, 18:32
The answers are x = - 1, 1, i√7/3, - i√7/3.
Solving by making a u-substitution, we let u = x² and rewrite the equation in quadratic form.
9u² - 2u - 7 = 0
We can now solve the quadratic equation by factoring. We need two numbers whose sum is - 2 and whose product is - 7. In this case, it would have to be 7 and - 1, considering the term 9u². Hence, we can also write our equation in the factored form
(u - 1) (9u + 7) = 0
Now we have a product of two expressions that is equal to zero, which means any u value that makes either (u - 1) or (9u + 7) zero will make their product zero.
u - 1 = 0 = > u = 1
9u + 7 = 0 = > u = - 7/9
We substitute back x² = u to calculate for x.
u = 1 = > x² = 1 = > x = - 1, 1
u = - 7/9 = > x² = - 7/9 = > x = i√7/3, - i√7/3
Therefore, the solutions are - 1, 1, i√7/3, and - i√7/3.
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» What are the solutions of the equation 9x^4 - 2x^2 - 7 = 0? Use u substitution to solve.