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5 August, 16:59

Using the definition of even and odd functions explain why y = sin x + 1 is neither even or odd?

Can you show how you worked it out cause I'm not sure on how to plug it in exactly

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  1. 5 August, 17:07
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    A function is even if, for each x in the domain of f, f ( - x) = f (x).

    The even functions have reflective symmetry through the y-axis.

    A function is odd if, for each x in the domain of f, f ( - x) = - f (x).

    The odd functions have rotational symmetry of 180º with respect to the origin.

    For y = without x + 1 we have:

    Let's see if it's even:

    f (-x) = sin (-x) + 1

    f (-x) = - sin (x) + 1

    It is NOT even because it does not meet f ( - x) = f (x)

    Let's see if it's odd:

    f (-x) = sin (-x) + 1

    f (-x) = - sin (x) + 1

    It is NOT odd because it does not comply with f ( - x) = - f (x)

    Answer:

    It is not even and it is not odd.
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