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A random sample of 250 working adults found that 74% access the Internet at work, 88% access the Internet at home, and 72% access the Internet at both work and home. Find the probability that a person in this sample selected at random accesses the Internet at home or at work.

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  1. 1 June, 23:48
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    The answer to the question is

    The probability is 0.9 or 90 %

    Step-by-step explanation:

    To solve the question, we note that

    Number of population sampled = 250

    Percentage that access the internet at work = 74 % = P (A)

    The number that access the internet at home = 88% while = P (B)

    The number that access the internet at home and at work = 72 % hence = P (C)

    The probability that a person in this sample selected at random accesses the Internet at home or at work is given by P (A) U P (B) - P (AnB)

    Which gives 0.74+0.88-0.72 = 0.9 or 90 %
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