Solve the system of linear equations by elimination. 5x=4y+8 5x=4y+8 3y=3x-3

Solve the following system using elimination:

{5 x = 4 y + 8 | (equation 1)

{3 y = 3 x - 3 | (equation 2)

Express the system in standard form:

{5 x - 4 y = 8 | (equation 1)

{ - (3 x) + 3 y = - 3 | (equation 2)

Add 3/5 * (equation 1) to equation 2:

{5 x - 4 y = 8 | (equation 1)

{0 x + (3 y) / 5 = 9/5 | (equation 2)

Multiply equation 2 by 5/3:

{5 x - 4 y = 8 | (equation 1)

{0 x+y = 3 | (equation 2)

Add 4 * (equation 2) to equation 1:

{5 x+0 y = 20 | (equation 1)

{0 x+y = 3 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 4 | (equation 1)

{0 x+y = 3 | (equation 2)

Collect results:

Answer: {x = 4

{y = 3