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28 August, 22:01

Write an equation of a line that is through (6,-3) and is perpendicular to 3x+y=6

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  1. 28 August, 22:17
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    Answer: y=-1/3x-1

    Step-by-step explanation:

    1) Isolate y by subtracting 3x from both sides.

    3x+y=6 - > y=3x+6

    2) Find the negative inverse of 3 - which is - 1/3.

    3) Use y=mx+b and plug in what you know.

    -3=-1/3 (6) + b

    4) Solve for b.

    -3=-2+b

    -1=b

    5) Put it all together in y=mx+b format.

    y=-1/3x-1
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