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18 December, 20:24

Dy/dx of y=sin3xcos2x?

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  1. 18 December, 20:44
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    dy/dx = d/dx (sin3x. cos2x)

    dy/dx = cos3x. 3. - sin2x. 2 (Using chain rule)

    dy/dx = - 6cos3xsin2x
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