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Zachariah
Mathematics
18 December, 20:24
Dy/dx of y=sin3xcos2x?
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Marley Flynn
18 December, 20:44
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dy/dx = d/dx (sin3x. cos2x)
dy/dx = cos3x. 3. - sin2x. 2 (Using chain rule)
dy/dx = - 6cos3xsin2x
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