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10 March, 02:43

The quotient of the complex # below (7-2i) / (4 + 3i)

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Answers (1)
  1. 10 March, 03:02
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    Step-by-step explanation:

    hello:

    (7-2i) / (4 + 3i)

    = (7-2i) * (4-3i) / (4 + 3i) * (4-3i)

    but : (7-2i) * (4-3i) = 28-21i-8i+6i²

    (7-2i) * (4-3i) = 22-29i ... i² = - 1

    (4 + 3i) * (4-3i) = 4² - (3i) ² ... (identity)

    = 16+9 = 25

    so:

    (7-2i) * (4-3i) / (4 + 3i) * (4-3i)

    = (22-29i) / 25

    (7-2i) / (4 + 3i) = 22/25 - 29/25i

    (form : a+ib)
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