Can you fine the cube root of a negative number? If so, is it positive or negative? Explain your answer.

- 3 √x) 3 = - (3 √x) 3 = - x

So - 3 √x is a cube root of - x

In terms of functions, f (x) = x3 is a continuous, unbounded, strictly monotonically increasing function of x.

Hence f (x) is one to one from Real numbers onto the Real numbers. Its domain and its range are the whole of the Real line R.