Use the identity a3+b3 = (a+b) 3-3ab (a+b) to determine the sum of the cubes of two numbers if the sum of the two numbers is 4 and the product of the two numbers is 1.

Enter your answer as a number, like this: 42

Question

Bosco

Mathematics

27 August, 05:04

Use the identity a3+b3 = (a+b) 3-3ab (a+b) to determine the sum of the cubes of two numbers if the sum of the two numbers is 4 and the product of the two numbers is 1.

Enter your answer as a number, like this: 42

+4

Answers (2)

Know the Answer?

Weiner · Answer 1

= 52

Step-by-step explanation:

Using the equation;

a3+b3 = (a+b) 3-3ab (a+b)

The sum, a+b = 4

The product, ab = 1

Therefore;

a3+b3=4³-3 (1) (4)

= 64-12

= 52

Kennedi Lowery · Answer 2

a³+b³ = 52

Step-by-step explanation:

We have given that

The sum of two numbers is 4.

The product of two numbers is 1.

a+b = 4

ab = 1

We have to find the sum of the cubes of two numbers.

a³+b³ = ?

Using given identity, we have

a³+b³ = (a+b) ³-3ab (a+b)

Putting given values in formula, we have

a³+b³ = (4) ³-3 (1) (4)

a³+b³ = 64-12

a³+b³ = 52 which is the answer.

Use the identity a3+b3 = (a+b) 3-3ab (a+b) to determine the sum of the cubes of two numbers if the sum of the two numbers is 4 and the product of the two numbers is 1.Enter your answer as a number, like this: 42

Use the identity a3+b3 = (a+b) 3-3ab (a+b) to determine the sum of the cubes of two numbers if the sum of the two numbers is 4 and the product of the two numbers is 1.

Enter your answer as a number, like this: 42