A cat chases a mouse. The cat is originally 4 feet behind the mouse, which is running in the same direction along the same route as the cat. If the cat's speed is 17 feet per second and the mouse's speed is 12 feet per second, how long will it take the cat to catch up with the mouse? (how many seconds?)

Question

Tara Gould

Mathematics

15 October, 04:08

A cat chases a mouse. The cat is originally 4 feet behind the mouse, which is running in the same direction along the same route as the cat. If the cat's speed is 17 feet per second and the mouse's speed is 12 feet per second, how long will it take the cat to catch up with the mouse? (how many seconds?)

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Answers (1)

Know the Answer?

Remington Marshall · Answer 1

Step-by-step explanation:

The position of the mouse at time t is 4 + 12t.

The position of the cat at time t is 17t.

When the positions are equal:

4 + 12t = 17t

4 = 5t

t = 0.8

It takes 0.8 seconds.