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13 May, 07:28

How many solutions are in the equation 3x^2+4x-7=0?

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  1. 13 May, 07:33
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    Hello:

    the equation 3x^2+4x-7=0 has 2 solutions because : ac < 0

    a = 3 b=4 c = - 7

    Δ = b²-4ac ... b² ≥ 0 and - 4ac > 0 ... (ac < 0)

    coclusion : Δ>0 ... (2 solutions)
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