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What is a polynomial function in standard form with zeros 1,-1,2, and 4

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  1. 5 May, 17:42
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    Because the zeros are 1, - 1, 2, 4, the factors are

    (x-1) (x+1) (x-2) (x-4)

    to put in standard form, you have to write the terms in order by degree, so you have to expand the above expression:

    (x^2-1) (x^2-6x+8)

    further expand it:

    x^4-6x^3+7x^2+6x-8
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