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30 May, 04:40

The sizes of seven exterior angles of an octagon are: 42, 110, 13, 67, 55, 11 and 53. What is the size of the eighth exterior angle?

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Answers (2)
  1. 30 May, 04:42
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    Step-by-step explanation:

    Always some of exterior angle of any polygon is 360

    42 + 110 + 13 + 67 + 55 + 11 + 53 + x = 360

    351 + x = 360

    x = 360 - 351

    x = 9
  2. 30 May, 05:07
    0
    9 degrees.

    Step-by-step explanation:

    For ALL polygons, the exterior angles add up to 360 degrees.

    Therefore the 8th exterior angle = 360 - (42+110+13+67+55+11+53)

    = 360 - 351

    = 9 degrees.
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