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28 September, 19:38

Gaussian surface 1 has twice the area of Gaussian surface 2. Both surfaces enclose the same charge Q. Is the electric flux through surface 1 greater than, less than, or the same as the electric flux through surface 2?

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  1. 28 September, 19:53
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    The electric flux through surface 1 is greater than the electric flux through surface 2.

    Step-by-step explanation:

    Electric Flux is given as:

    Φ = E*A

    where E = Electric field

    A = surface area.

    For surface 1,

    Φ (1) = E (1) * A (1)

    For surface 2,

    Φ (2) = E (2) * A (2)

    Since both surfaces have the same charge, the electric fields will be the same.

    Hence, E (1) = E (2) = E

    From the question we are given that:

    A (1) = 0.5A (2)

    Hence,

    Φ (1) = E*A (1)

    Φ (2) = E*A (2) = E*0.5A (1)

    Φ (2) = 0.5E*A (1)

    Comparing Φ (1) and Φ (2), we see that Φ (1) is 2 time greater than Φ (2), hence, the Flux through surface 1 is greater than the Flux through surface 2.
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