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5 May, 00:23

What is the center and radius of the circle with the equation x2 + y2 - 10x - 12y + 36 = 0?

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  1. 5 May, 00:48
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    X² + y² - 10 x - 12 y + 36 = 0

    (x² - 10 x + 25) + (y² - 12 y + 36) - 25 - 36 + 36 = 0

    (x - 5) ² + (y - 6) ² = 25

    (x - 5) ² + (y - 6) ² = 5²

    Answer:

    The center: (5, 6), the radius: r = 5
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