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21 February, 21:34

The area of the triangle can be represented by the expression 14x^5+63x^2. if the base is 7x^2, write an expression to represent its height.

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Answers (2)
  1. 21 February, 21:43
    0
    The first thing you should know for this case is that the area of a triangle is given by:

    A = (1/2) * (b) * (h)

    Where,

    b: base.

    h: height.

    Clearing the height we have:

    h = ((2) * (A)) / (b)

    Substituting the values

    h = ((2) * (14x ^ 5 + 63x ^ 2)) / (7x ^ 2)

    Simplifying the expression:

    h = ((2) * (2x ^ 3 + 9))

    h = 4x ^ 3 + 18

    answer

    an expression to represent its height is

    h = 4x ^ 3 + 18
  2. 21 February, 21:59
    -1
    Area of a triangle = 1/2 * b * h where b and h are the base and height.

    Hence 1/2 * b * h = 14x^5+63x^2.

    Since b = 7x^2; we have

    1/2 * 7x^2 * h = 14x^5 + 63x^2.

    Multiply both sides by 2 and divide both sides by 7x^2

    h = 2 * (14x^5+63x^2) / 7x^2

    h = (28x^5 + 126x^2) / 7x^2

    h = (28/7) x^ (5-2) + (126/7) x^ (2-2)

    h = 4x^3 + 18x^ (0)

    h = 4x^3 + 18
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