How many terms are in the arithmetic sequence - 27, - 16, - 5, ..., 292?

Hint: a_n=a_1+d (n-1), where a_1 is the first term and d is the common difference

Question

Zaria Franklin

Mathematics

6 April, 07:21

How many terms are in the arithmetic sequence - 27, - 16, - 5, ..., 292?

Hint: a_n=a_1+d (n-1), where a_1 is the first term and d is the common difference

+2

Answers (1)

Know the Answer?

Piper Zavala · Answer 1

A (n) = a (1) + d (n-1)

in this case, a (n) = 292, a (1) = - 27, d=-16 - (-27) = 11

292=-27+11 (n-1)

11 (n-1) = 319

n-1=29

n=30

there are 30 terms.

How many terms are in the arithmetic sequence - 27, - 16, - 5, ..., 292?Hint: a_n=a_1+d (n-1), where a_1 is the first term and d is the common difference

How many terms are in the arithmetic sequence - 27, - 16, - 5, ..., 292?

Hint: a_n=a_1+d (n-1), where a_1 is the first term and d is the common difference