Ask Question
14 September, 07:08

A system of equations is shown.

0.6d+0.05e=-4.5

-0.12d+0.3e=2.76

d=

e=

+1
Answers (1)
  1. 14 September, 07:24
    0
    I would multiply to get rid of the decimals and work with whole numbers.

    Since we have numbers that are "hundredths", we would need to multiply every number by 100.

    60d + 5e = - 450

    -12d + 30e = 276 Now that the decimals are gone, if we multiply the second equation by 5 the "d's" will cancel.

    60d + 5e = - 450

    -60d + 150e = 1380

    155e = 930

    e = 6

    Now plug 6 back in for e and solve for d.

    60d + 5 (6) = - 450

    60d + 30 = - 450

    60d = - 480

    d = - 8

    (-8, 6)

    If you'd rather work it with decimals just let me know.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A system of equations is shown. 0.6d+0.05e=-4.5 -0.12d+0.3e=2.76 d= e= ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers