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27 February, 07:38

A chemist needs to mix an 20% acid solution with a 50% acid solution to obtain 15 liters of a 34% acid solution. How many liters of each of the acid solutions must be used?

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Answers (2)
  1. 27 February, 07:43
    0
    8 litres of the 20% and

    7 litres of the 50% solution.

    Step-by-step explanation:

    Let the number of litres be x for 20% and y for the 50% solution. Then

    0.2x + 0.5y = 15*0.34

    0.2x + 0.5y = 5.1 Also we have:

    x + y = 15 Multiply the first equation by - 2:

    -0.4x - y = - 10.2 Adding these last 2 equations:

    0.6x = 4.8

    x = 4.8 / 0.6

    x = 8.

    and y = 15 - 8 = 7.
  2. 27 February, 07:57
    0
    8 and 7

    Step-by-step explanation:

    No Need
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