The parabola y=x^2-2x+4 will have a vertex of

The vertex is at (h, k) = > (1, 3)

Step-by-step explanation:

Complete the square of y=x^2 - 2x + 4 to determine the coordinates of the vertex.

Note that the first two terms of y=x^2 - 2x + 4 resemble the perfect square (x - 1) ^2:

y=x^2 - 2x + 4 = > y = (x^2 - 2x + 1) + 4 - 1, or

y = (x - 1) ^2 + 3

Comparing this last result to the standard equation y = (x - h) ^2 + k, we see that h = 1 and k = 3. The vertex is at (h, k) = > (1, 3)