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2 November, 18:26

Tickets to a show cost $10 in advance and $15 at the door. If 120 tickets are sold for a total of $1,390, how many of the tickets were bought in advance?

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  1. 2 November, 18:54
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    Let x = number of tickets bought in advance

    y = number of tickets bought at the door

    We have two unknowns therefore we need to equations to solve the problem. We do as follows:

    x + y = 120

    10x + 15y = 1390

    SOlving simultaneously,

    x = 82

    y = 38
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