If sinX = 0.6, and X is in Quadrant II, then what is the value of cosX?

To calculate for cos X given that sin X=0.6 and is in Quadrant we proceed as follows:

sin X=0.6

Thus implies that:

x=arcsin 0.6

x=36.97

given that X is in the Quadrant ii then the value of x will be:

180-36.97

=143.13

hence cos X will be:

cos X=cos 143.13

cos X=-0.8