F (t) = 3t^2-2 find f (k-2)

The answer is f (k - 2) = 3k² - 12k + 10

The function is: f (t) = 3t² - 2

We need to find f (k - 2). Since t = k - 2, we will just substitute t in the function:

t = k - 2

f (t) = 3t² - 2

f (k - 2) = 3 (k - 2) ² - 2 =

= 3 (k² - 2 * k * 2 + 2²) - 2 =

= 3 (k² - 4k + 4) - 2 =

= 3k² - 3*4k + 3*4 - 2 =

= 3k² - 12k + 12 - 2 =

= 3k² - 12k + 10