Solve 2x2 + 3x - 7 = x2 + 5x + 39 for x.

A. x=-6 + or - the square root of 82

B. x=-6 + or - 2 with the square root of 17

C. x=1 + or - the square root of 33

D. x = 1 + or - the square root of 47

Question

Camryn Ritter

Mathematics

15 April, 16:11

Solve 2x2 + 3x - 7 = x2 + 5x + 39 for x.

A. x=-6 + or - the square root of 82

B. x=-6 + or - 2 with the square root of 17

C. x=1 + or - the square root of 33

D. x = 1 + or - the square root of 47

+1

Answers (1)

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Emerson Mcmahon · Answer 1

2x2 + 3x - 7 = x2 + 5x + 39

2x2 + 3x - 7 - x2 - 5x - 39=0

x2 - 2x - 46 = 0

(x-1) 2 - 46 - 1 = 0

(x-1) 2 - 47=0

(x-1) 2 = 47

x-1 = + or - the square root of 47

x = 1 + or - the square root of 47

Solve 2x2 + 3x - 7 = x2 + 5x + 39 for x.A. x=-6 + or - the square root of 82B. x=-6 + or - 2 with the square root of 17C. x=1 + or - the square root of 33D. x = 1 + or - the square root of 47

Solve 2x2 + 3x - 7 = x2 + 5x + 39 for x.

A. x=-6 + or - the square root of 82

B. x=-6 + or - 2 with the square root of 17

C. x=1 + or - the square root of 33

D. x = 1 + or - the square root of 47