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17 February, 18:03

What is the factor of 16^2-81

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  1. 17 February, 18:06
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    This is the diffiarence of two perfect squares. this should be memorised, but if not here it is

    a^2-b^2 = (a-b) (a+b)

    so 16^2-81=16^2-9^2

    so the answer is (16-9) (16+9)
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