Identify the vertical asymptotes of f (x) = 2 over quantity x squared plus 3 x minus 10.

The function is:

f (x) = 2 / (x² + 3 x - 10)

x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x (x + 5) - 2 (x + 5) =

= (x + 5) (x - 2)

x + 5 = 0 = > x = - 5

x - 2 = 0 = > x = 2

Answer:

The vertical asymptotes are: x = - 5 and x = 2.