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11 June, 13:57

Identify the vertical asymptotes of f (x) = 2 over quantity x squared plus 3 x minus 10.

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  1. 11 June, 14:08
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    The function is:

    f (x) = 2 / (x² + 3 x - 10)

    x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x (x + 5) - 2 (x + 5) =

    = (x + 5) (x - 2)

    x + 5 = 0 = > x = - 5

    x - 2 = 0 = > x = 2

    Answer:

    The vertical asymptotes are: x = - 5 and x = 2.
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