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17 October, 20:25

Given ƒ (x) = 3x - 1 and g (x) = - x + 6, find ƒ (-2) + g (5).

-6

6

8

+4
Answers (2)
  1. 17 October, 20:26
    0
    f (x) = 3x - 1

    g (x) = - x + 6

    f (2) + g (5) = (3 (2) - 1) + ( - (5) + 6)

    f (2) + g (5) = (6 - 1) + (-5 + 6)

    f (2) + g (5) = 5 + 1

    f (2) + g (5) = 6

    The answer is C.
  2. 17 October, 20:33
    0
    This should be the answer

    Given ƒ (x) = 3x - 1 and g (x) = - x + 6, find ƒ (-2) + g (5).

    f (-2) = 3 (-2) = - 6 - 1 = - 7

    g (5) = - (5) = - 5 + 6 = 1

    -7+1 = - 6

    Answer: - 6
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