What is the completely factored form of x3 - 64x?

x (x - 8) (x - 8)

(x-4) {x^2+4x+16}

x (x - 8) (x + 8)

(x - 4) (x + 4) (x + 4)

Question

Curtis Marquez

Mathematics

30 January, 15:59

What is the completely factored form of x3 - 64x?

x (x - 8) (x - 8)

(x-4) {x^2+4x+16}

x (x - 8) (x + 8)

(x - 4) (x + 4) (x + 4)

+1

Answers (2)

Know the Answer?

Nola Dudley · Answer 1

Remember difference of 2 perfect squares

a²-b² = (a-b) (a+b)

first factor out x

x (x²-64)

x (x²-8²)

x (x-8) (x+8)

answer is 3rd option

Stephen · Answer 2

The answer is x (x-8) (x+8)

Here is the process;

x^3-64x

x (x^2-64)

You know that it will be a x - and a x + becuase there is no middle x value

x (x-) (x+)

x (x-8) (x+8)

What is the completely factored form of x3 - 64x?x (x - 8) (x - 8)(x-4) {x^2+4x+16}x (x - 8) (x + 8)(x - 4) (x + 4) (x + 4)

What is the completely factored form of x3 - 64x?

x (x - 8) (x - 8)

(x-4) {x^2+4x+16}

x (x - 8) (x + 8)

(x - 4) (x + 4) (x + 4)