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21 May, 06:23

Ten less than five times a number is less than six times the number decreased by eight

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  1. 21 May, 06:36
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    10 - 5x < 6x - 8

    We can treat this inequality like a normal algebraic equation.

    Add 5x to both sides

    10 < 11x - 8

    Add 8 to both sides

    18 < 11x

    Divide both sides by 11

    1.64 < x

    X is greater than the value 1.64.

    Let's plug the number 2 into each value of x to verify.

    10 - 5x < 6x - 8

    10 - 5*2) < (6 * 2) - 8

    10 - 10 < 12 - 8

    0 < 4

    It's correct.

    Now let's plug 1, which is less than 1.64.

    10 - 5x < 6x - 8

    10 - 5 < 6 - 8

    5 < - 2

    This is not correct, which means that our answer was correct.
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