1. Put 9y=-3x-39 into standard form

2. Put - 2x+2y=-2 into standard form

3. Solve the system by either using substitution or elimination{-2x=20,

3x-4y=-2}

4.

1. Put 9y=-3x-39 into standard form

3x + 9y = - 39 ... this is standard form

2. Put - 2x+2y=-2 into standard form

2x - 2y = 2 ... this is standard form

3. Solve the system by either using substitution or elimination

{-2x=20, 3x-4y=-2}

-2x = 20

x = - 10

substitute x = - 10 into 3x-4y=-2

3x-4y=-2

3 (-10) - 4y=-2

-30 - 4y = - 2

4y = - 28

y = - 7

answer

x = - 10 and y = - 7

1. 9y = - 3x - 39 ... add 3x to both sides

3x + 9y = - 39 < = = standard form

2. - 2x + 2y = - 2 ... multiply by - 1

2x - 2y = 2 < = = standard form

3. - 2x = 20

x = - 20/2

x = - 10 ... now sub this back into the second equation

3x - 4y = - 2

3 (-10) - 4y = - 2

-30 - 4y = - 2

-4y = - 2 + 30

-4y = 28

y = - 28/4

y = - 7

solution is (-10,-7) < = = solution