Determine the type and number of solutions of x2 - 12x + 36 = 0.

First you would solve for x. Since the equation follows the square of a binomial rule, you would solve it so.

(a - b) ^2 = a^2 - 2ab + b^2

a^2 = x^2

a = x

b^2 = 36

b = 6

x^2 - 12x + 36 = (x - 6) ^2 = 0

x = 6

There is one real solution.

Quadratic formula and the solution is 6