4x-y + 2z=-1

Given the system - x+2y + 5z = 2, which is true?

|-x+y-3z = 1

Y = 0

X = 1/2

Z = - 1/2

Step-by-step explanation:

4x-y + 2z=-1

-x+y-3z = 1

-x+2y + 5z = 2

Solving simultenously

Y = 4x + 2z - 1

Y = 1 + 3z + x

Y = x/2 - (5z/2) - 1

Equating y will give two equations

3x-z = 2

3x + 11z = - 4

Subtracting the equations

-12z = 6

Z = - 1/2

Substituting z

3x + 1/2 = 2

3x = 3/2

X = 1/2

Substituting x and z to find y in

-x+y-3z = 1

-1/2 + y + 3/2 = 1

Y = 1-1

Y = 0