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Snowball
Mathematics
7 June, 03:41
What is an x intercept of x^2-64
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Rebecca Guzman
7 June, 03:58
0
Answer: (8,0) and (-8,0)
Step-by-step explanation: It is one positive and one negative 8 because a double positive would be a + 64 and a double negative would also be a + 64 (unless there was another x for example x^2+2x-64.
x^2-64
(x+8) (x-8)
(x+8) (x-8) = 0
x+8=0 and x-8=0
(-8,0) and (8,0)
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Noe Bradshaw
7 June, 04:02
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(8,0) (-8,0) are the x intercepts
Step-by-step explanation:
Factor
x^2 - 64
This is the difference of squares
(x-8) (x+8)
Set equal to zero to find the intercepts
x-8 = 0 x+8 = 0
x = 8 x = - 8
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