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Callum Cuevas
Mathematics
1 February, 17:45
What is the product (4+8i) (2-3i)
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Abril Holloway
1 February, 17:59
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(4+8i) (2-3i)
=8 - 12i + 16i - 24i^2
i^2 = - 1
=8+4i - 24 (-1)
=8+4i+24
=32+4i
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