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13 October, 14:17

2/3y^2+14=20 How do you solve this with the square root method?

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  1. 13 October, 14:34
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    y1 = - 3, y2 = 3

    Step-by-step explanation:

    (2/3) y^2 + 14 = 20

    (2/3) y^2 = 20 - 14

    (2/3) y^2 = 6

    y^2 = 9

    y = - 3 and y = 3
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