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31 March, 14:43

The 4th term of a geometric sequence is 135, and the common ratio is 3. What is the first term of the sequence?

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  1. 31 March, 15:07
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    Assume the first term is a. The second term is 3a. The third term is 9a. The forth term is 27a.

    27a=135 therefore a=135/27 = 5
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