Craig is designing a new cylinder-shaped can for a pet food company. He wants the height of the can to be 40 mm and the radius of the can to be 1 3/8 times the height of the can. He models the can on a coordinate grid as a rectangle in the first quadrant that will be rotated around the y-axis to create the 3-dimensional can. What will be the diameter of the can?

Question

Dax Christensen

Mathematics

12 September, 22:41

Craig is designing a new cylinder-shaped can for a pet food company. He wants the height of the can to be 40 mm and the radius of the can to be 1 3/8 times the height of the can. He models the can on a coordinate grid as a rectangle in the first quadrant that will be rotated around the y-axis to create the 3-dimensional can. What will be the diameter of the can?

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Answers (1)

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Taryn Decker · Answer 1

The height of the can for this case is given by:

h = 40 mm

The radius of the can is given by:

r = (1 3/8) * h

Substituting values:

r = (1 3/8) * 40

r = 55 mm

Therefore, the diameter of the can is:

d = 2 * r

d = 2 * 55

d = 110 mm

Answer:

The diameter of the can will be:

d = 110 mm