Problem page the length of a rectangle is 6 cm longer than its width. if the perimeter of the rectangle is 40 cm, find its area.

P = 2 (L + W)

P = 40

L = W + 6

40 = 2 (W + 6 + W)

40 = 2 (2W + 6)

40 = 4W + 12

40 - 12 = 4W

28 = 4W

28/4 = W

7 = W ... so the width is 7 cm

L = W + 6

L = 7 + 6

L = 13 ... and the length is 13 cm

the area is the length times the width

A = L * W

A = 13 * 7

A = 91 cm^2 <===