The weights of six animals at the zoo are shown in the table below. weights of animals (pounds) 5 24 38 52 66 85 what is the mean absolute deviation? round to the nearest tenth.

Mean absolute deviation is the average distance of the data from the mean.

Mean = [5+24+38+52+66+85]/6 = 270/6 = 45

Distances of each data from the mean

|5-45| = 40

|24-45| = 21

|38-45| = 7

|52-45|=7

|66-45| = 21

|85-45| = 40

Average of the distances = [40+21+7+7+21+40]/6 = 136/6 = 22.7

Answer: 22.7