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Ruben Fields
Mathematics
12 May, 16:46
Completely factor 4a^2-12a+8
+2
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2
)
Alfredo Duffy
12 May, 17:11
0
4 (a-1) (a-2)
Step-by-step explanation:
take out 4 (common factor)
4 (a^2-3a+2)
then use box method to factor
a - 1
a a^2 - a
-2 - 2a 2
4 (a-1) (a-2)
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Donna Giles
12 May, 17:16
0
4 (a - 2) (a - 1)
Step-by-step explanation:
4a^2 - 12a + 8 =
First, factor out a common factor from all terms.
= 4 (a^2 - 3a + 2)
To factor a^2 - 3a + 2, you need two numbers whose product is 2 and whose sum is - 3. Since the product is a positive number, 2, the two numbers are either both positive or both negative. Since the sum is negative, - 3, then both numbers must be negative. The two numbers are - 1 and - 2.
= 4 (a - 2) (a - 1)
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