Ron buys a lawnmower for $1,500. The salesperson says the value will depreciate about 30% per year over the next few years. However, his neighbor says it is likely to depreciate about $300 per year.

Which system could be used to determine when the two depreciation models will give the same value for the lawnmower?

y = 1,500 (0.3) x and y = 1,500 - 300x

y = 1,500 (0.7) x and y = 300 - 1,500x

y = 1,500 (0.7) x and y = 1,500 - 300x

y = 1,500 (0.3) x and y = x - 300

Question

Dominick Chandler

Mathematics

16 April, 17:46

Ron buys a lawnmower for $1,500. The salesperson says the value will depreciate about 30% per year over the next few years. However, his neighbor says it is likely to depreciate about $300 per year.

Which system could be used to determine when the two depreciation models will give the same value for the lawnmower?

y = 1,500 (0.3) x and y = 1,500 - 300x

y = 1,500 (0.7) x and y = 300 - 1,500x

y = 1,500 (0.7) x and y = 1,500 - 300x

y = 1,500 (0.3) x and y = x - 300

+1

Answers (1)

Know the Answer?

Gallagher · Answer 1

For the first part, we know that we start at 1500$. Next, we know that we have 100% of the 1500$ at the start. After that, it depreciates at 30%, so we have (100-30) %=70%, and 70/100=0.7, so it multiplies by 0.7 every year, and the answer is either the second or third one. For the second part, we know that we start at 1500 dollars - it cannot go higher than that, but it has to be that at the start (x=0, or no time has passed). Next, we subtract 300 for every year, so after x years, it has depreciated 300*x times. Therefore, for the amount of money it's worth, we have y=1500-300x and the answer is the third option

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