The second of two numbers is 6 times the first. their sum is 84. find the numbers

X = first numbery = second number Since the second of there two numbers is 6 times the first, this means y equals 6 times x. Therefore, the equation formed will be y = 6x. The second condition is that the same of the two numbers 77. Therefore:x + y = 77Since y = 6x, we can substitute y for 6x and get x + 6x = 77. Simplifying this we get 7x = 77. Therefore, x = 11. We found out the first number, x, equals 11. To find out what y is, we just plug it back into the equation x + y = 77. Therefore, 11 + y = 77 - - > y = 66 Answer: The first number equals 11, and the second number equals 66.