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16 January, 12:42

Find the zeros of the function (x+3) ^2 (x-5) ^6 and state the multiplicity

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  1. 16 January, 12:45
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    Find the zeros of Function (x) = (x+3) ^2 (x-5) ^6 and state the multiplicity ... (x--5) ^6 = 0=> x--5 = 0 = > x = 5. Therefore real zero's of the function are - - 3,5.
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